expand p until we find a sequence of 100 successive 0's let this happen at the n^th digit.

then up till n is identical with p

if n is odd let terminate at the n^th digit < p

if n is even let have a 1 in the (n + 1)^th place > p . Consider the number Q where

Q = - p .

Is Q positive, zero, negative?

Constructionalists say that none is true. Q will be ?????

at such time that someone determines which in this case

???Is maths useful? "......doing pure mathematics is making meaningless scribbles on a piece of paper according to certain rules"

David Hilbert 1862 - 1943